the value of 7cos^2A+7sin^2A-3 is
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7 sin²A + 3 cos²A = 4
=> 3 sin²A + 3 cos²A + 4 sin²A = 4
=> 3 ( sin²A + cos²A ) + 4 sin²A = 4
=> 3 + 4 sin²A = 4
=> 4 sin²A = 1
=> sin²A = 1/4
=> sin A = 1/2
=> sin A = sin 30°
=> A = 30° .
So , tan A = tan 30° = 1/√3
Answered by
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7 cos2a + 7sin2a - 3
= 7(cos2a + sin2a)-3
= 7*1 -3
=7-3
=4
hope it helps
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