Question

The value of (-9/16
$| (x + y)(x - y)$
​

Answer 1

Is your question -$\frac{9}{16}$(x + y)(x - y)?

Answer:

-$\frac{9x^{2} - 9y^{2}}{16}$

Step-by-step explanation:

  -$\frac{9}{16}$(x + y)(x - y)

= -$\frac{9}{16}$(x² - y²)

= -$\frac{9x^{2} }{16}$ - -$\frac{9y^{2} }{16}$

= -$\frac{9x^{2} }{16}$ + $\frac{9y^{2} }{16}$

= -$\frac{9x^{2} - 9y^{2}}{16}$

Hope it's helpful.