Question

the value of (9/4+under root 6)raise power 2 (9/4-under root 6) raise power 2

Answer 1

Using (a+b)(a-b) = a^2-b^2
this implies:
$( \frac{9}{4} ) ^{2} - (\sqrt{6} ) ^{2} \\ \frac{81}{16} - 6 \\ \frac{(81 - 16 \times 6)}{16} \\ - \frac{15}{16}$I guess this is the answer!
hope it helps!