Question

the value of 9 sec square 60 degree minus 9 tan square 60 degree is​

Answer 1

Answer:

9 sec2 A - 9 tan2 A

= 9( sec2 A - tan2 A)

= 9 × 1

= 9

Answer 2

Answer:

Required value of the 9 sec square 60 degree minus 9 tan square 60 degree is 9.

Step-by-step explanation:

Given,9 sec square 60 degree minus 9 tan square 60 degree

Or,$9 {sec}^{2} {60}^{o} - 9 {tan}^{2} {60}^{o}$

We are taking 9 common from each term.

$9( {sec}^{2} {60}^{o} - {tan}^{2} {60}^{o} )$

We know,

${sec}^{2} x - {tan}^{2}y = 1$

So,

$9( {sec}^{2} {60}^{o} - {tan}^{2} {60}^{o} ) \\ = 9 \times 1 \\ = 9$

Therefore, required value of the given expression is 9.

This is a problem of Trigonometry.

Some important Trigonometry formula:

$sin(x) = \cos(\frac{\pi}{2} - x) \\ \tan(x) = \cot(\frac{\pi}{2} - x) \\ \sec(x) = \csc(\frac{\pi}{2} - x) \\ \cos(x) = \sin(\frac{\pi}{2} - x) \\ \cot(x) = \tan(\frac{\pi}{2} - x) \\ \csc(x) = \sec(\frac{\pi}{2} - x)$

know more about Trigonometry,

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