The Value of
a+a^a(a), when a=3 is....
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4
3 + 3³( 3 )
3 + 27 × 3
3 + 81
84
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a.a=a^2
so the question is a^a^2+a
when a=3, it becomes 3^3^2+3
= 3^9+ 3
=19683+3
=19686
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