Math, asked by vikashumar98756, 17 days ago

The value of a car depreciates 20% every year. If after two years, the price of a car is 420000, find the original price of the car?​

Answers

Answered by gausia8080
1

Answer:

656250

Step-by-step explanation:

Given data,

  • The value of a car depreciates 20% every year.
  • The price of the car after two years is 420000.
  • Let the price of the car one year ago be x.

According to the given data,

x-x\times\frac{20}{100}=420000

\Rightarrow x-\frac{x}{5}=420000

\Rightarrow \frac{4x}{5}=420000

\Rightarrow x=525000

  • Let the original price of the car be y

y-y\times\frac{20}{100} =525000

\Rightarrow y-y\times\frac{20}{100}=525000

\Rightarrow y-\frac{y}{5}=525000

\Rightarrow \frac{4y}{5} =525000

\Rightarrow y=656250

Hence, the original price of the car is 656250.

Answered by junaida8080
0

Answer:

656250

Step-by-step explanation:

Given,

  • The value of a car depreciates 20% every year.
  • The price of the car after two years =420000
  • Let the original price of the car be x
  • Then the price of the car after one year

=x-x\times\frac{20}{100}

=x-\frac{x}{5}

=\frac{4x}{5}

  • Now, the price of the car after two years

=\frac{4x}{5}-\frac{4x}{5}\times\frac{20}{100}

=\frac{4x}{5}-\frac{4x}{25}

=\frac{20x-4x}{25}

=\frac{16x}{25}

  • According to the given data

\frac{16x}{25} =420000

\Rightarrow x=656250

Hence, the original price of the car is 656250.

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