Question

the value of a for which the lines x=1,y=2 & a^2x+2y-20=0 are concurrent is

Answer 1

HERE IS THE ANSWER OF YOUR QUESTION :-

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a^2x + 2y - 20 = 0 ........(1)

given = x = 1 and y = 2

Put value of x and y in equation (1) then we get,

a^2 + 4 - 20 = 0

a + 8 - 40 = 0

a = 32


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HOPE IT HELPS YOU.

Answer 2

Given: Here we have given $x=1,y=2$ & $a^2x+2y-20=0$

To find: Here we have to the value of a

Solution:

Here we have the given equation

$a^2x + 2y - 20 = 0$

we also have given = x = 1 and y = 2

now we will put value of x and y in the given equation then we get,

$a^2 + 4 - 20 = 0\\a + 8 - 40 = 0\\a = 32$

Hence the value of a is 32

Final answer:

Hence the value of a is 32