The value of a, if the value of -x2+3x-a is equal to 8, whenx=-1,is
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Answer:
23x=82x+1
⟹23x=(23)2x+1
⟹23x=(23x)2+1
And now we have the equation in a more manageable form and something about it resembles a quadratic equation but not with those exponents so the next step is:
Let A=23x
Which leaves us with:
A=A2+1
Rearranging and solving for 0:
A2−A+1=0
Step-by-step explanation:
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