Question

the value of a machine depreciate every year at the rate of 10% per annum . if present value of machine is 8000 . what is percent decrease in its value in three years?​

Answer 1

Step-by-step explanation:

hey here is your solution ,

let the value of machine after 3years be

$x$

$the \: value \: of \: machine \: after \: 3year \: = {8000(1 - \frac{10}{100} })^{3}$

$x = 8000 \times \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10} \\ \\ x = 5832$

so,

$value \: decreased \: = rs(8000 - 5832) =rs \: 2168$

$\% \: of \: decrease = \frac{2168}{8000} \times 100$

$= 27.1\%$

Answer 2

• Value Depreciates by every year = 10%

• Present value of the machine is = 8000

10% of 8000 is = 800

• It means in one year the machine value will depreciate by 800

• So after three years, the value of the machine is = 800×3= 2400

8000-2400= 5600

• After three years the machine value Is = 5600

• Percentage decreases in its value per year is 10% so in three years it is decreasing by 30% approximately 26%