Question

The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8,748, its purchase price was ?

Answer 1

Let the principal be ₹x
amount =8,748
time =3 years.
Amount = p(1-r/100)power n ( when rate is d-
epreacting)
A/q
8748 = x(1-10/100)power 3
==> 8748=x ×9/10×9/10×9/10
==>8748= x × 729/1000
==>8748×1000= x × 729
==>8748000/728 =x
==>12000=x
hence x = 12000
so , the machine was purchased in ₹ 12000

HOPE IT WILL HELP YOU ✌✌

Answer 2

let the Principal be = ₹x

Amount = ₹8748 and Time = 3years

.

8748 = x(1-10/100)^3

8748 = x × 9/10 × 9/10 × 9/10

8748 = x × 729/1000

8748 × 1000= x × 729

8748000/729 = x

12000 = x

.

hence,the purchase price was ₹12000

.

hope it helped☺️