The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 years ago. If it's present value is rupees 291600, for how much was it purchased?
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Answered by
11
Purchase price = 291600/(1-10/100)^3
= 291600 * 10/9 * 10/9 * 10/9
= 400000.
= 291600 * 10/9 * 10/9 * 10/9
= 400000.
Answered by
5
op=291600
R=10%
t=3 years
then amount is
=291600 (1-10/100)^3
=2916×9×9×9/10
=212576.4
R=10%
t=3 years
then amount is
=291600 (1-10/100)^3
=2916×9×9×9/10
=212576.4
7209186598av:
No
and ans is 400000
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