the value of a machine depreciates at the rate of 20% per annum it was purchased two years ago if its present value is 40000 rupees for how much was it purchased
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Answer:
A=P(1-r/100)^T
A=40000(1-20/100)^2
=40000*80/100*80/100
=40000*4/5*4/5
=4000*4*4
=Rupees 64000.
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