Question

The value of a machine depreciates bt 10 % annually . If its present value is ₹ 100000 , what will be its value after 2 years .

Answer 1

rate of depreciation per annum(r) = 10%
present value(p)= 100000 rs
time(n) = 2 years
after 2 years the value of the machine will be
$= p {(1 - \frac{r}{100} )}^{n} \\ = 100000 {(1 - \frac{10}{100} )}^{2} \\ = 100000 \times \frac{90}{100} \times \frac{90}{100} \\ = 10 \times 90 \times 90 \\ = 81000 \: rs$

Answer 2

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Step-by-step explanation:

Step-by-step explanation:

P=1,00,000

R=10%

T=2 Years

Depreciated Amount= P x (1-R/100) ²

=1,00,000 x (1-10/100)²

=1,00,000 x (9/10)²

=1,00,000 x 9/10 x 9/10

=1,00,000 x 0.9 x 0.9

=1,00,000 x 0.81

=       81,000