Question

The value of a machine reduces 10% every year.if it was purchased 3years ago. if it's present value is 8748, it's purchase price was?
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Answer 1

$\large \mathtt{Let \: the \: principal \: be \: ₹x}$

$\large \mathtt{amount =8,748}$

$\large \mathtt{time =3 years.}$

$\implies \large \mathtt{</p><p>Amount = p {( \frac{1 - r}{100} )}^{n} }$

$\large \mathtt{According \: To \: Question}$

$\implies\mathtt{8748 = x { \frac{1- 10}{100} }^{3}}$

$\implies \mathtt{8748=x × \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10} }$

$</p><p> \implies \mathtt{8748= x × \frac{729}{1000} }$

$\implies \mathtt{</p><p>8748×1000= x × 729}$

$\implies \mathtt{\frac{8748000}{728} =x}$

$\implies \mathtt{12000=x}$

$\large \mathtt{So , \: the \: machine \: was \: purchased \: in \: ₹ 12000}$