Question

The value of a machine reduces by 20%
every year. If the present value is 15,000,
what was its value be 2 years later?​

Answer 1

Answer:

Rate of depreciation = 20%

Present value = Rs. 15000

Value after two years later

$= present \: value \times {(1 - \frac{rate \: of \: depreciation}{100} )}^{2} \\ = 15000 \times {(1 - \frac{20}{100} )}^{2} \\ = 15000 \times {(1 - \frac{1}{5}) }^{2} \\ = 15000 \times {(\frac{4}{5})}^{2} \\ = 15000 \times \frac{16}{25} \\ = 600 \times 16 \\ = 9600$

Answer 2

Step-by-step explanation:

Answer:

Rate of depreciation = 20%

Present value = Rs. 15000

Value after two years later

\begin{gathered} = present \: value \times {(1 - \frac{rate \: of \: depreciation}{100} )}^{2} \\ = 15000 \times {(1 - \frac{20}{100} )}^{2} \\ = 15000 \times {(1 - \frac{1}{5}) }^{2} \\ = 15000 \times {(\frac{4}{5})}^{2} \\ = 15000 \times \frac{16}{25} \\ = 600 \times 16 \\ = 9600\end{gathered}

=presentvalue×(1−

100

rateofdepreciation

)

2

=15000×(1−

100

20

)

2

=15000×(1−

5

1

)

2

=15000×(

5

4

)

2

=15000×

25

16

=600×16

=9600