Question

the value of air resistance depend only on the size of the object true or false​

Answer 1

hey mate...

here is your answer...

The density of air (ρ). This typically has a value around 1.2 kg/m3.

The cross sectional area of the object (A). A ping pong ball would have a cross sectional area equal to π*r2.

The drag coefficient (C). This depends on the shape of the object. For a spherical object, a unitless value of 0.47 is typical.

The magnitude of the velocity squared. The faster you go, the greater the air resistance force.

The direction of the air resistance force is in the opposite direction as the velocity of the object. That's why there is a negative sign in the expression along with the r - hat (which is a unit vector in the direction of the velocity).

But how do you find values for the drag coefficients for different objects? The real answer is that you must measure them experimentally. However, Wikipedia has a nice list of some values. What about a falling human? I often have to model the motion of a falling human, but there isn't a C value listed. There is one trick I can use.

The trick involves terminal velocity. Suppose a human jumps out of a stationary hot air balloon. At first, only the gravitational force acts on the human giving an acceleration of -9.8 m/s2. However, as the human increases in speed, the air resistance force also increases. At some point, the air resistance force will be equal in magnitude to the gravitational force and the human will no longer increase in speed. We call this "terminal velocity".

Now for the trick. It seems to be mostly accepted that the terminal velocity for a skydiver is about 120 mph (53.6 m/s). Of course, this is the terminal velocity for the normal skydiving position with head facing down and arms and legs spread out. If I guess at a human mass of 70 kg, I can set the air resistance and gravitational forces equal. Also, for simplicity I am going to call all the constants in front of the velocity squared just K (since they don't change).

hope it helps...

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