Question

the value of cos ^-1 (-x)=
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Answer 1

Answer:

Here θ has infinitely many values. Let 0 ≤ α ≤ π2, where α is positive smallest numerical value and satisfies the equation cos θ = x then the angle α is called the principal value of cos−1 x. Therefore, cos−1 x = 2nπ ± α, where, 0 ≤ α ≤ π and (- 1 ≤ x ≤ 1).

I think so

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