Question

The value of cos(90°-????)sec(90°-????)tan????/cosec(90°-????)sin(90°-????)+tan(90°-????)/cot???? is
A. 1
B. - 1
C. 2
D. - 2

Answer 1

Answer:

option A is the right answer

Answer 2

A. 1

Step-by-step explanation:

cos(90°-θ) sec(90°-θ) tanθ / cosec(90°-θ) sin(90°-θ) + tan(90°-θ)/ cotθ = cos(90°-θ). 1/cos(90°-θ). tanθ / 1/sin (90°-θ). sin(90°-θ) + tan(90°-θ)/ tan(90°-θ)

[because 1/cosθ = secθ; 1/sinθ = cosecθ; cotθ = tan(90-θ)°]

So LHS becomes  tanθ / 1 + 1 = tanθ + 1 .

Assuming θ is zero degrees, we get LHS = tanθ + 1 = tan 0° + 1 = 0 + 1 = 1

Option A is the answer.