Question

The value of cot (- 1470°)​

Answer 1

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

TO DETERMINE

$\sf{ \cot( - {1470}^{ \circ} ) \:}$

CALCULATION

STEP : 1

$\sf{Since \: \cot \theta \: \: is \: an \: odd \: function }$

So

$\sf{ \cot( - {1470}^{ \circ} ) \:} = - \: \sf{ \cot {1470}^{ \circ} \:}$

STEP : 2

$\sf{{1470}^{ \circ} = 16 \times {90}^{ \circ} + {30}^{ \circ} \:}$

So

$\sf{ \cot( - {1470}^{ \circ} ) \:}$

$= - \: \sf{ \cot {1470}^{ \circ} \:}$

$= - \: \sf{ \cot (16 \times {90}^{ \circ} + {30}^{ \circ} ) \:}$

STEP : 3

$\sf{The \: angle \: {1470}^{ \circ } \: lies \: in \: First \: Quadrant }$

Hence all the steps leads to final result as

$\sf{ \cot( - {1470}^{ \circ} ) \:}$

$= - \: \sf{ \cot {1470}^{ \circ} \:}$

$= - \: \sf{ \cot (16 \times {90}^{ \circ} + {30}^{ \circ} ) \:}$

$= - \: \sf{ \cot {30}^{ \circ} \:}$

$= - \sqrt{3}$

RESULT

$\boxed{\sf{ \: \: \cot( - {1470}^{ \circ} ) \:} = - \sqrt{3} \: \: \: \: }$

━━━━━━━━━━━━━━━━

LEARN MORE FROM BRAINLY

Find the value of cot (-3155°)

https://brainly.in/question/6963315