The value of cot[π/4 - cot⁻¹3] is......,Select Proper option from the given options.
(a) 3
(b) 7
(c) 9
(d) 3/4
Answers
Answered by
3
we have to find the value of cot[π/4 - cot^-1(3)]
Let cot^-1(3) = A
then, cotA = 3 .........(1)
now , cot[π/4 - cot^-1(3)] = cot(π/4 - A)
we know, formula , cot(A - B) = (cotA.cotB + 1)/(cotB - cotA)
so, cot(π/4 - A) = (cotπ/4.cotA + 1)/(cotA- cotπ/4)
= (cotA + 1)/(cotA - 1)
now put equation (1),
= (3 + 1)/(3 - 1) = 2
hence, option is incorrect.
answer should be 2
Let cot^-1(3) = A
then, cotA = 3 .........(1)
now , cot[π/4 - cot^-1(3)] = cot(π/4 - A)
we know, formula , cot(A - B) = (cotA.cotB + 1)/(cotB - cotA)
so, cot(π/4 - A) = (cotπ/4.cotA + 1)/(cotA- cotπ/4)
= (cotA + 1)/(cotA - 1)
now put equation (1),
= (3 + 1)/(3 - 1) = 2
hence, option is incorrect.
answer should be 2
Answered by
6
HELLO DEAR,
GIVEN:-
cot[π/4 - cot-¹(3)]
Let cot-¹(3) = A SO, cotA = 3
now , cot[π/4 - cot-¹(3)] = cot(π/4 - A)
WE KNOW, cot(A - B) = (cotA.cotB + 1)/(cotB - cotA)
so, cot(π/4 - A) = (cotπ/4.cotA + 1)/(cotA- cotπ/4)
[as , cotπ/4 = 1]
= (cotA + 1)/(cotA - 1)
AND [cotA = 3]
=> (3 + 1)/(3 - 1) = 2
hence, answer is 2
I HOPE ITS HELP YOU DEAR,
THANKS
GIVEN:-
cot[π/4 - cot-¹(3)]
Let cot-¹(3) = A SO, cotA = 3
now , cot[π/4 - cot-¹(3)] = cot(π/4 - A)
WE KNOW, cot(A - B) = (cotA.cotB + 1)/(cotB - cotA)
so, cot(π/4 - A) = (cotπ/4.cotA + 1)/(cotA- cotπ/4)
[as , cotπ/4 = 1]
= (cotA + 1)/(cotA - 1)
AND [cotA = 3]
=> (3 + 1)/(3 - 1) = 2
hence, answer is 2
I HOPE ITS HELP YOU DEAR,
THANKS
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