the value of cot(-4050)
Answers
Answer:
iL.H.S.
=tan225
0
cot405
0
+tan765
0
cot675
0
=tan(360
0
−135
0
)cot(360
0
+45
0
)+tan(2∗360
0
+45
0
)cot(2∗360
0
−45
0
)
=(−tan135
0
)(cot45
0
)+(tan45
0
)(−cot45
0
)
=−tan135
0
cot45
0
–tan45
0
cot45
0
=−tan(180
0
–45
0
)cot45
0
–tan45
0
cot45
0
=−(−tan45
0
)cot45
0
–tan45
0
cot45
0
=tan45
0
cot45
0
–tan45
0
cot45
0
=0
=R.H.S.
Hence Proved.
Answer:
0
Step-by-step explanation
We know,
cot360=cot1440
or, cot360=cot(4*360)
So, we can use 1440 instead of 360 since the value of cot360 and cot1440 are same.
= cot(-4050)
= -cot(4050)
= -cot(1440+2610)
= -cot(2610) {cot(1440+∅ ) = cot∅}
= -cot(1440+1170)
= -cot(1170) {cot(1440+∅ ) = cot∅}
= -cot(1440-270)
= -cot(-270) {cot(1440-∅ ) = cot(-∅)}
= -1*-cot(270) {cot(-∅)= -cot∅}
= cot270
= cot(270-0)
= tan0 {∵cot(270-∅) = tan∅}
= 0
[Used only CAST rule]