Question

the value of cot (sin^1 x) is​

Answer 1

Step-by-step explanation:

If your question is cot(sin^(-1) x).

  Let sin^(-1) x = A

           ⇒ sinA = x

    ⇒ height/hypot. = x

Let, height be ax and hypotenuse be a.

Using Pythagoras theorem,

        ⇒ base^2 = a^2 - (ax)^2

        ⇒ base = √a² - a²x²

        ⇒ base = a√(1 - x²)

Therefore,

  cotA = base/height

           = a√(1 - x²) / ax

           = √(1 - x²)/x

Hence,

cot(sin^(-1) x) = cotA = √(1 - x²)/x

Answer 2

√1-x²/x ɪꜱ ᴛʜᴇ ᴀɴꜱᴡᴇʀ ᴏꜰ yᴏᴜʀ qᴜᴇꜱᴛɪᴏɴ