Question

..The value of current in the 60 n resistance of the circuit
shown, is
60.12
150
1 AS
(a) 1/6 A
(c) 0.1 A
(b) 1/3 A
(d) 0.5 A
wahhh​

Answer 1

Answer: I don't know

Explanation:

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Answer 2

Answer:

The circuit's current value in the 60 resistance is 0.1A.

Explanation:

• The resistors 15Ω and 5Ω are connected in series. So, their equivalent resistance is 20Ω.
• And the resistors 60Ω, 20Ω, and 10Ω are in parallel so the voltage across them will remain the same.
• The net resistance of the parallel combination is,

        $\frac{1}{R}= \frac{1}{R_1} +\frac{1}{R_2}+ \frac{1}{R_3}$     (1)

We can get the following results by plugging values into equation (1):

    $\frac{1}{R}= \frac{1}{60} +\frac{1}{20}+ \frac{1}{10}$

    $\frac{1}{R}=\frac{1+3+6}{60}$

    $R=\frac{60}{10}$

    $R=6 \ volt$          (2)

The overall voltage across the system is calculated as follows:

  $V=6\times 1=6\ volt$   (3)

The current through the 60Ω resistor is calculated as,

$I=\frac{V}{60}$

$I=\frac{6}{60}$

$I=0.1 \ A$

As a result, the current in the circuit's 60 resistance is 0.1A.

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