Triangle ABC is an equilateral triangle with AC =8; find the area of this triangle
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Answer:
the area of triangle is 27.71 unit square
Step-by-step explanation:
given that AC(a)=8 unit
area of triangle=(√3/4)*a²
=(√3/4)*64
=16√3
=27.71unit square
Answered by
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ac= 8 cm
all sides are equal in an equilateral triangle.
therefore, ab=bc=ca
area of equilateral triangle = √3/4 x s^2
= √3/4 x 8^2
= √3/4 x 64
= √3 x 16
= √3= 1.732
= 1.732 x 16
= 27.712
therefore, area of triangle is 27.712 cm^2
all sides are equal in an equilateral triangle.
therefore, ab=bc=ca
area of equilateral triangle = √3/4 x s^2
= √3/4 x 8^2
= √3/4 x 64
= √3 x 16
= √3= 1.732
= 1.732 x 16
= 27.712
therefore, area of triangle is 27.712 cm^2
chaturvarma:
sorry the units of answer is cm^2
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