Question

The value of equilibrium constant of the reaction
HI(g) ⇌ 1 H₂ (g) + 1 I₂ is 8.0
2 2
The equilibrium constant of the reaction
H₂ (g) + I₂ (g)⇌2HI(g) will be:
(a) 1 (b) 1
16 64
(c) 16 (d) 1
8

Answer 1

Answer:

hey your ans is 1/64.

....

Answer 2

(a) 1/16

Explanation:

Given: 2 HI  ⇌ H2 + I2 is 8.0, 2, and 2.

To find: value of equilibrium constant.

Solution:

 Keq = [H2] [I2] / [HI]²

 = 2 * 2 / 8²

 = 1/(2*8)

 = 1/16

Option A is the answer.