The value of expression [cosec ( 75degree + q ) - sec ( 15 degree - q - tan ( 55 degree + q + cot ( 35 degree - q ) ] is
(A) -1
(B)0
(C)1
(D)3/2
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Answer:
(B) 0
Explanation:
[cosec(75°+q) - sec(15°-q) - tan(55°+q) + cot(35°-q)]
Use the identities:
sec a = cosec(90-a)
sec a = cosec(90-a) tan a = cot(90-a)
= [cosec(75°+q) - cosec(90-(15-q) - cot(90-(55+q) + cot(35-q)]
= [cosec(75+q) - cosec(90-15+q) - cot(90-55-q) + cot(35-q)]
= [cosec(75+q) - cosec(75+q) - cot(35-q) + cot(35-q)]
= 0
Hope it helps.........
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