Question

The value of g on the earth's surface is 980 cm/s2 it's value at height 64 km from the surface is ?
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Answer 1

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Answer 2

The value of g on the height of 64 km is $9.604\ m/s^2$.

Explanation:

It is given that,

Value of g on the Earth surface, $g=980\ cm/s^2=9.8\ m/s^2$

Height, $h=64\ km=64\times 10^3\ m$

The value of g at a height h is given by :

$g'=g(1-\dfrac{2h}{r})$

g is the acceleration due to gravity on earth's surface

r is the radius of Earth, r = 6400 km

$g'=9.8\times (1-\dfrac{2\times 64\times 10^3}{6400\times 10^3})$

$g'=9.604\ m/s^2$

So, the value of g on the height of 64 km is $9.604\ m/s^2$. Hence, this is the required solution.

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The value of g on the earth's surface is $980\ cm/s^2$ it's value at height 64 km from the surface is?

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