the value of g on the moon 1/6 of the value of g on the earth.if a man can jump 1.5 m high on the earth,on the moon,be can jump up to height of
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9
It's simple to calculate!
S = u*t + 1/2* a*t^2
Where ,
S - is the displacement
u- is the intial velocity
a-is the acceleration due to gravity
t-is the time
This is the equation of motion (derived with the help of calculus) in one dimension when acceleration is a constant.
Considering a free fall from a given height (here given height is S) where initially the object is stationary. Going by the equation , the time taken would amount to (2S/a)^0.5
For earth :
Let a = g;
So t= (2*S/g)^0.5
For moon:
Let a= g/6
So t=(12*S/g)^0.5
Thus , the object would fall for a longer time in moon with approximately 2.45 times the time it takes to fall in earth.
S = u*t + 1/2* a*t^2
Where ,
S - is the displacement
u- is the intial velocity
a-is the acceleration due to gravity
t-is the time
This is the equation of motion (derived with the help of calculus) in one dimension when acceleration is a constant.
Considering a free fall from a given height (here given height is S) where initially the object is stationary. Going by the equation , the time taken would amount to (2S/a)^0.5
For earth :
Let a = g;
So t= (2*S/g)^0.5
For moon:
Let a= g/6
So t=(12*S/g)^0.5
Thus , the object would fall for a longer time in moon with approximately 2.45 times the time it takes to fall in earth.
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5
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