Question

The value of gravitation constant in 6.67 * 10^-11 M m^2 Kg^-2 convert into cgs system.

Answer 1

Solution:

Given:

$\sf{\implies Gravitational\;constant = 6.67\times 10^{-11}\;Nm^{2}kg^{-2}}$

To Find:

=> Change into CGS system.

Formula used:

$\sf{\implies n_{2}=n_{1}\bigg(\dfrac{M_{1}}{M_{2}}\bigg)^{a}\;\bigg(\dfrac{L_{1}}{L_{2}}\bigg)^{b}\;\bigg(\dfrac{T_{1}}{T_{2}}\bigg)^{c}}$

So, according to formula,

$\sf{\implies 6.67\times 10^{-11}\bigg(\dfrac{kg}{gram}\bigg)^{-1}\;\bigg(\dfrac{meter}{cm}\bigg)^{3}\;\bigg(\dfrac{sec}{sec}\bigg)^{-2}}$

$\sf{\implies 6.67\times 10^{-11}\;\bigg(\dfrac{1000\;g}{g}\bigg)^{-1}\;\bigg(\dfrac{100\;cm}{cm}\bigg)^{3}}$

$\sf{\implies 6.67\times 10^{-11}\times \dfrac{1}{1000}\times 100\times 100\times 100}$

$\sf{\implies 6.67\times 10^{-11}\times 10^{3}}$

$\large{\boxed{\boxed{\purple{\sf{\implies 6.67\times 10^{-8}\;dyne\;cm^{2}\;g^{-2}}}}}}$

Answer 2

$\huge\underline\green{\underline{Solution \:is\: attached\:here.}}$