the value of iCAP.(iCAP*jCAP) IS
Answers
Answered by
5
Answer: 0
Explanation:
assuming that your question should have been i ( i . j )..
we know that..the dot product of unit vectors i and j is..
i . j = 0
that is,
i ( i . j ) = i ( 0 ) = 0
∴ the value of iCAP.(iCAP*jCAP) IS (0).
hope that helps...
Answered by
2
Answer:
The value of icap.(icapXjcap) is 0
Explanation:
It is assumed that the equation is icap.(icap X jcap)
Using the thumb rule
icap X jcap would direct in the direction of kcap
Therefore icap X jcap = kcap
Now, icap.kcap
icap.kcap = 0 as the dot product between similar vectors is 1 whereas the dot product between different vectors is 0.
Therefore icap.(icapXjcap) = 0
Ans: The value of icap.(icapXjcap) is 0.
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