Chemistry, asked by Anonymous, 4 months ago

the value of isothermal expansion of an ideal gas into vaccum is

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Answered by rakhip1980

Answer:

When an ideal gas is subjected to isothermal expansion (∆T = 0) in vacuum the work done w = 0 as pex=0. As determined by Joule experimentally q =0, thus ∆U = 0.

Explanation:

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