Question

The value of k for which equ equation,
2x²-kx+k=0 has equal root is
a)-4 b)4 c)8 d)-8​

Answer 1

Step-by-step explanation:

D=0{given}

D=b2-4ac

here a=2,b=-k,c=k

so,

0={-k}^2-4{2}{k}

0=k^2-8k

k{k-8}=0

k=0,k=8

according to your options:-

option c is correct

hope it will help you

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Answer 2

Answer

c) 8

The value of k is 8 or 0

$\bf\large\underline{Given}$

The quadratic equation is:

• 2x² - kx + k = 0
• The roots of the given equation are equal

$\bf\large\underline{To \ Find}$

• The value of k

$\bf\large\underline{Solution}$

We are given that the roots of the equation 2x² - kx + k = 0 are equal

So , its discriminant

D = 0

$\sf\implies {b}^{2} - 4ac = 0 \\ \\ \sf\implies( - k) {}^{2} - 4 \times 2 \times k = 0 \\ \\ \sf \implies {k}^{2} - 8k = 0 \\ \\ \sf \implies k(k - 8) = 0$

Therefore ,

$\sf \implies k = 0 \: \:or\: \implies k = 8$

Thus , the value is of k is 0 or 8