Math, asked by amnabawazir123, 6 months ago

Write all possible zeroes of the polynomial p(x) = (x +2 ) ( x – 3 ) ( x – 5 )

Answers

Answered by aryan073
0

Step-by-step explanation:

p(x)=x(x-3)+2(x-3)(x-5)

p(x)=(x²-x-6)(x-5)

x²(x-5)-x(x-5)-6(x-5)

x³-5x²-x²+5x-6x+30=0

x³-6x²-x+30=0

x=3

x=5

x=-2

Answered by manasipatro32
0

Answer:

p(x)= -2, 3 and 5

Step-by-step explanation:

p(x)= x+2

If x=-2,

then p(x)= -2+2

=0

p(x)= x-3

If x=3,

then p(x)=3-3

=0

p(x)=x-5

If x=5

then p(x)=5-5

=0

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