the value of k for which equations 3x+5y+2=0 and kx+10y+ 4=0 have many solution is
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Answer:
k = 6
Step-by-step explanation:
Condition for many solutions is
a1/a2 = b1/b2=c1/c2 where a1=3, b1=5,c1=2 and a2=k, b2=10, c2=4
3/k = 5/10
k = 3 × 10/5 = 6
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