Question

The value of k for which the equation below has equal roots x²+2(k+1)x+k²=0​

Answer 1

Answer:

Therefore, the value of k is (- 1/2).

Answer 2

Given x

2

−2(k+1)x+k

2

=0 has real and equal roots

As we know that

for a quadratic equation to have real and equal roots ,discriminant should be zero

⟹(−2(k+1))

2

−4(1)(k

2

)=0

⟹(k+1)

2

−k

2

=0

⟹2k+1=0

⟹k=−

2

1

Step-by-step explanation:

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