The value of k, for which the numbers x, 2x + k and 3x + 6 are three consecutive terms of an AP is
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Step-by-step explanation:
It is given that ,
x ,2x+k and 3x+6 are three consecutive terms .
/* we know that ,
Difference of any two consecutive terms is equal in A.P */
Now,
(2x+k)-x = (3x+6)-(2x+k)
=> 2x+k-x = 3x+6-2x-k
=> x+k = x+6-k
=> k+k = x+6-x
=> 2k = 6
=>k = 6/2
=> k = 3
Therefore,
If k = 3 then the given three consecutive terms x,2x+k and 3x+6 are in A.P
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