Question

The value of k, for which the numbers x, 2x + k and 3x + 6 are three consecutive terms of an AP is​

Answer 1

Answer:

Step-by-step explanation:

It is given that ,

x ,2x+k and 3x+6 are three consecutive terms .

/* we know that ,

Difference of any two consecutive terms is equal in A.P */

Now,

(2x+k)-x = (3x+6)-(2x+k)

=> 2x+k-x = 3x+6-2x-k

=> x+k = x+6-k

=> k+k = x+6-x

=> 2k = 6

=>k = 6/2

=> k = 3

Therefore,

If k = 3 then the given three consecutive terms x,2x+k and 3x+6 are in A.P

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