Question

The value of k for which the pair of equations kx – y = 2 and 6x – 2y = 4 will have infinitely many solutions is (A) 3 (B) – 3(C) –12 (D) no value​

Answer 1

Answer:

Solution:-

For a system of equations a1x+b1y+c1=0;a2x+b2y+c2=0  to have unique solution, the condition to be satisfied is

a2a1=b2b1=c2c1

⇒6k=−2−1=32

∴ For unique solution of system of equations, k=3,4

Answer 2

Answer✍

a1/a2 = b1/b2 = c1/c2

k/6 = -1/-2 = -2/-3

Consider first two terms

k/6 = 1/2

k = 3

Therefore option A is correct.

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