Question

The value of k for which the pair of equations kx-y=2 and 6x-2y=3 has a unique solution is

Answer 1

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Answer 2

The value of k is not equal to 3.

Step-by-step explanation:

Given : Equation $kx-y=2,6x-2y=3$

To find : The value of k for which the pair of equations has a unique solution ?

Solution :  

When the system of equation is in form $ax+by+c=0, dx+ey+f=0$ then the condition for unique solutions is  

$\frac{a}{d}\neq\frac{b}{e}$

On comparing, a=k, b=-1, c=-2, d=6, e=-2, f=-3

Substituting the values,

$\frac{k}{6}\neq \frac{-1}{-2}$

$\frac{k}{6}\neq \frac{1}{2}$

$k\neq \frac{6}{2}$

$k\neq3$

Therefore, The value of k is not equal to 3.

#Learn more

Find the value of k for which the pair of equations kx-y=2 and 6x-2y=3 will have no solution

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