Question

The value of k for which the pair of linear equation 4x+6y-1=0 & 2x+ky-7=0 represents parallel lines is ? (a) k=3(b)k=2(c)k=4(d)k=-2

Answer 1

THERE IS THE SOLUTION


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Answer 2

Answer:

The value of k is 3.

Option (a) is correct.

Step-by-step explanation:

Given the equations of two lines 4x+6y-1=0 & 2x+ky-7=0

we have to find the value of k for which the above two lines are parallel.

The two lines are

$4x+6y-1=0.....line 1$

$2x+ky-7=0......line 2$

$\text{As the slope of line ax+by+c=0 is }\frac{-a}{b}$

$\text{Therefore the slope of line 1 is }\frac{-4}{6}$

$\text{The slope of line 2 is }\frac{-2}{k}$

Also the slope of parallel lines are equal

⇒ $\frac{-4}{6}=\frac{-2}{k}$

Cross-multiplying both sides

$-4k=-12$

$k=\frac{-12}{-4}=3$

Hence, the value of k is 3.

Option (a) is correct.