Question

The value of k for which the pair of linear equations 4x+6y-1=0 and 2x+ky-7=0 represents parallel lines is. a)k=3 b)k=2 c)k=4 d)k=-2

Answer 1

Answer: a)k=3

Step-by-step explanation:

The pair of linear equation represents parallel lines if:

$\frac{a1}{a2}=\frac{b1}{b2} \neq \frac{c1}{c2}$

For the given pair of equation 4x + 6y - 1 = 0 and 2x + ky - 7 = 0;

$\frac{a1}{a2} = \frac{4}{2} = 2$

$\frac{b1}{b2} = \frac{6}{k}$

$\frac{c1}{c2} = \frac{-1}{-7} = \frac{1}{7}$

For $\frac{a1}{a2} = \frac{bi}{b2}$

      ⇒ k = 3

The pair of linear equation represents parallel lines for k = 3.