Question

The value of k for which the points A(0,1) B (2,k) and C(4, -5) are collinear is?

Answer 1

$\huge \underline \bold \color{fuchsia} \mathfrak{Answer}$

For the points A(0,1), B(2,k), C(4,-5) to be collinear,

x1(y2-y3) +x2(y3-y1) +x3(y1-y2) =0

0(k+5)+2(-5-1)+4(1-k)=0

0+2×-6+4-4k=0

-12+4=4k

-8=4k

k=-2

Answer 2

The answer is

$\huge\bold\color{red}{-2}$