Question

An urn contains 14 black balls, 12 blue balls and 10 green balls. If a ball is drawn randomly what is the probability of getting

I) a blue ball
II) not a green ball
III) either a black or green ball​

Answer 1

Answer:

Total balls=14+12+10=36

1)Probability of getting a blue ball =12/36

2)Probability of not a green ball=12+14=26/36

3)probability of getting either a black or green ball=24/36

Answer 2

Answer:

total number of outcomes = 14+12+10 =36

I) number of Blue Balls = 12

probability of getting a blue ball = 12/36= 3

II) number of green ball= 10

probability of not getting a green ball = 36-10/36 = 13/12

III) number of green and black ball = 14+10= 24

probability of getting a green ball either a black ball = 24/36 = 2/3

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