Question

the value of k for which the quadratic eqn. 4x^2+4√3x+k=0 has equal roots is​

Answer 1

given equation :- 4x² + 4√3x + k

here, a = 4, b = 4√3 and c = k

nature of quadratic equation is determined by D

if D is 0, then the equation have two equal roots.

D = (b)² - 4ac

since it has equal zeroes

➡ b² - 4ac = 0

➡ (4√3)² - 4(4)(k) = 0

➡ 48 - 16k = 0

➡ -16k = -48

➡ k = -48/-16

➡ k = 3

hence, the value of k is 3.

Answer 2

$\huge\textbf\green{Answer:-}$

According to the given question:-

4x² + 4√3x + k

• Let Q= 4
• A = 4√3
• M = k

b² - 4ac = 0

(4√3)² - 4(4)(k) = 0

$(48 - 16k = 0)$

$-16k = -48 \\ </p><p>k = -48/-16 \\ </p><p> k = 3$

Therefore ,3 is the value of k