Math, asked by Bindi8875, 7 months ago

The value of k for which the system kx-y-2=0 and 6x-2y-3=0 have no soltion

Answers

Answered by Sschaudharyoo1in
0

Answer:

k=3

Step-by-step explanation:

we know that for a system of equation having no solution

a1/a2=b1/b2≠c1/c2

now , we have  kx-y-2=0

                         6x-2y-3=0

k/6=-1/-2

k=3

Hence, the value of k for which the system kx-y-2=0 and 6x-2y-3=0 have no solution is 3

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