Question

the value of K for which the system of equations 2x-3y = 7 and (k + 1)x + (1-2k)y = 5k-4 hads infintely many soluitons

Answer 1

Step-by-step explanation:

2x-3y=7

(k+1)x+(1-2k)y=5k-4

a1 = b1 = c1

a2 b2 c2

2 = 7

(k+1) 5k-4

2 (5k-4)=7 (k+1)

10k-8=7k+7

10k-7k=7+8

3k=15

k=15

3

k=5

Therefore K=5