the value of k if (2x-1)is a 6xsq+kx-2
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Given:-
2x - 1 is a factor of the given equation.
To find:-
The value of k
Solution:-
2x - 1 is a factor therefore,
2x - 1 = 0
2x = 1
x = 1/2 is a zero of the polynomial.
Substituting the value of x in the polynomial,
6(1/2)² + k(1/2) - 2 = 0
6×1/4 + k/2 - 2 = 0
3/2 + k/2 - 2 = 0
3/2 + k/2 - 4/2 = 0
(3 + k - 4)/2 = 0
3 + k - 4 = 0
k - 1 = 0
k = 1
The value of k is 1.
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