The value of k if kx^2 + 2(k+1)x+(3k+1)=0 has real and equal roots
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D= 0 (Condition For Equal Roots)
4(k+1)^2-4k(3k+1) = 0
4[k2+1+2k]-12k2-4k=0
4k2+4+8k-12k2-4k=0
-8k2+4k+4=0
2k2-k-k=0
2k2-2k+k-1=0
2k(k-1)+1(k-1)=0
(2k+1)(k-1)=0
k = -1/2 or 1
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