Question

The value of kp for the reaction 2so2 + o2 =2so3 is 5 what will be the partial pressure of o2 when equal moles of so2 and so3 present at equilibrium

Answer 1

For the given reaction:

2SO₂ + O₂ ---->2SO₃

Kp can be calculated as:

$Kp=\frac{[PSO_{3}^{2}]}{[PSO_{2}^{2}]\times [PO_{2}]}$

As given:

[PSO₃]=[PSO₂]

So,  

$5=\frac{[1}{[O_{2}]}$

$[PO_{2}]=\frac{[1}{[5]}$

$[PO_{2}]=\frac{[1}{[5]}$

$[PO_{2}]=0.2$

So, partial pressure of oxygen will be 0.2 atm.

0.2 atm will be the partial pressure of O₂.

Answer 2

Answer:

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