Question

The value of m so that 4x2-6x-m is divisible by x-3,is exact divisor of

Answer 1

p(3)= 4(3)^2-6(3)-m
= 36-18-m=0
= -18+m
m= 18

Answer 2

Answer:

m=18

Step-by-step explanation:

We need to find the value of m so that $4x^2-6x-m$ is divisible by x-3.

If a polynomial P(x) is completely divisible by (x-c), then P(c)=0.

The given polynomial is

$P(x)=4x^2-6x-m$

If this polynomial is completely divisible by (x-3), then P(3)=0.

Substitute x=3 in the given polynomial.

$P(3)=4(3)^2-6(3)-m$

$P(3)=4(9)-18-m$

$P(3)=36-18-m$

$P(3)=18-m$

The value of P(3) is 0.

$P(3)=0$

$18-m=0$

Add m on both sides,

$18=m$

Therefore, the value of m is 18.