Question

The value of machine depreciates at the rate 20% per annum it was purchased two years ago if its present value is 40000 rupees for how was it purchase

Answer 1

Answer:

Hey mate..!!

Here is the answer...

$40000(1 - \frac{20}{100} ) {}^{2}$

$= 40000 \times \frac{4}{5} \times \frac{4}{5}$

$= 25600$

Brainliest please..